How do I clone a list so that it doesn’t change unexpectedly after assignment?
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In Python 3, a shallow copy can be made with:
In Python 2 and 3, you can get a shallow copy with a full slice of the original:
new_list = my_list
doesn’t actually create a second list. The assignment just copies the reference to the list, not the actual list, so bothnew_list
andmy_list
refer to the same list after the assignment.To actually copy the list, you have several options:
list.copy()
method (available since Python 3.3):Alex Martelli‘s opinion (at least back in 2007) about this is, that it is a weird syntax and it does not make sense to use it ever. 😉 (In his opinion, the next one is more readable).
list()
function:copy.copy()
:This is a little slower than
list()
because it has to find out the datatype ofold_list
first.copy.deepcopy()
: